You intend to conduct an ANOVA with 7 groups in which each group will have the same number of subjects: n=6n=6. (This is referred to as a "balanced" single-factor ANOVA.) 1. What are the degrees of freedom for the numerator?
d. f.(treatment) =
2. What are the degrees of freedom for the denominator?
d. f.(error) =

d.f.(treatment) = 6

d.f.(error) = 35

Step-by-step explanation:

In the question we have

k = 7

r= 6

n= rk= 42

1. The degrees of freedom for the numerator is calculated as under

d.f.(treatment) = k-1= 7-1= 6

Where k gives the number of columns

2. The degrees of freedom for the denominator is calculated as under

d.f.(error) = k (r-1)= n-k= 42-7=35

where k gives the number of columns and r gives the number of rows.

This is for one way ANOVA as asked above.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24