Consider the line 9x+5y=6 What is the slope of a line parallel to this line? What is the slope of a line perpendicular to this line?

The equation of the line is 9x-5y=9

5y=9x-9

y=9/5x-9/5

Comparing with y=mx+c we get slope m=9/5

Slope of a line parallel to this line=9/5

Slope of a line perpendicular to this line=-5/9

Step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

21

jk it's 20

step-by-step explanation: