A calculus exam that was taken by 94 students is recorded and normally distributed. The mean score on the exam is 78 and the standard deviation is 2.4. What percent of the scores are in the 70.8 and 85.2 range?

99.73%

Step-by-step explanation:

If you have a calculator with distribution functions, this problem boils down to using a single command:

norm(70.8, 85.2, 78, 2.4) = 0.9973

This tells us that 99.73% of the scores are in the 70.8-85.2 range.

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet