Point P is in the interior of ∠OZQ. If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ?

Step-by-step explanation:

If point P is in the interior of ∠OZQ, then ∠OZQ = ∠OZP+∠PZQ. Given m∠OZQ = 125 and m∠OZP = 62, to get m∠PZQ, we will substitute the value of the angles given into the expression above as shown;

∠OZQ = ∠OZP+∠PZQ.

125 = 62 + ∠PZQ.

subtract 62 from both sides;

125 - 62 = 62 + ∠PZQ -62

63 = ∠PZQ

Hence the angle  m∠PZQ is 63°

the answer is  

a.

4,624π mm2

step-by-step explanation: