Which set of ordered pairs was generated by the equation y= x+5?

( − 2 , − 7 )  

( − 1 , − 6 )

( 0 , − 5 )

( 1 , − 4 )

( 2 , − 3 )

Step-by-step explanation:

Because  x  is our independent variable, we choose the  x  integers and solve for  y .

Usually, the five typical  x  integers are  − 2 , − 1 , 0 , 1 , and  2 .

If  x = − 2 , we can plug that number in for  x  in our main equation.  − 2 − 5 = − 7 , so if  x = − 2 ,  y = − 7 . (  2 , − 7 ) .

We'd continue with this step for the next four numbers.

If  x = − 1 , − 1 − 5 = − 6 , so if  x = − 1 , then  y = − 6 .

( − 1 , − 6 ) .  

If  x = 0 , 0 − 5 = − 5 , so if  x = 0 , then  y = − 5 . ( 0 , − 5 ) .  

If  x = 1 , 1 − 5 = − 4,  so if  x = 1 , then  y = − 4 .

( 1 , − 4 ) .  

If  x = 2 , 2 − 5 = − 3 , so if  x = 2 , then  y = − 3 . ( 2 , − 3 ) .

hope this helps

i think it is c, not positive though

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°