Using prime factorization method , find the HCF b)18 and 15
c)16 ,32 and 48
e)27, 63 and 54

see explanation

Step-by-step explanation:

(b)

18 = 2 × 3 × 3 = 2 × 3²

15 = 3 × 5

The common prime factor = 3

HCF = 3

(c)

16 = 2 × 2 × 2 × 2 =

32 = 2 × 2 × 2 × 2 × 2 =

48 = 2 × 2 × 2 × 2 × 3 = × 3

The common prime factor =

HCF = = 16

(e)

27 = 3 × 3 × 3 = 3³

63 = 3 × 3 × 7 = 3² × 7

54 = 2 × 3 × 3 × 3 = 2 × 3³

The common prime factor = 3²

HCF = 3² = 9

answer: it's d

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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