Which corrects Indira’s first error? Indira should have substituted B (negative 6, 1) right-arrow B prime (negative 3 + a, negative 2 + b) = B prime (negative 6, 1) in Step 1. Indira should have written the equations Negative 6 + a = negative 3 and 1 + b = negative 2 in Step 2. Indira should have solved the equations to find that a = negative 8 and b = negative 2 in Step 3. Indira should have written the translation rule (x, y) right-arrow (x minus 4, y + 4) in Step 4.

Indira should have written the equations Negative 6 + a = negative 3 and 1 + b = negative 2 in Step 2.

Step-by-step explanation:

The complete question is:

On a coordinate plane, point B(–6, 1) is translated to B prime(–3, –2). Indira uses these steps to find a rule to describe the translation. Step 1Substitute the original coordinates and the translated coordinates into (x, y) right-arrow (x + a, y + b):

B (negative 6, 1) right-arrow B prime (negative 6 + a, 1 + b) = B prime (negative 3, negative 2)

Step 2

Write two equations:

Negative 6 + a = negative 2. 1 + b = negative 3.

Step 3

Solve each equation:

Negative 6 + a = negative 2. a = negative 2 + 6. a = 4. 1 + b = 3. b = negative 3 minus 1. b = negative 4.

Step 4

Write the translation rule:

(x, y) right-arrow (x + 4, y minus 4)

Which corrects Indira’s first error?

Indira should have substituted B (negative 6, 1) right-arrow B prime (negative 3 + a, negative 2 + b) = B prime (negative 6, 1) in Step 1.

Indira should have written the equations Negative 6 + a = negative 3 and 1 + b = negative 2 in Step 2.

Indira should have solved the equations to find that a = negative 8 and b = negative 2 in Step 3.

Indira should have written the translation rule (x, y) right-arrow (x minus 4, y + 4) in Step 4.

Transformation is the movement of a point from its initial position to a new position. Types of transformation is rotation, dilation, rotation or reflection.

Translation is the movement of a point in a given direction. It is represented by (x, y) ⇒ (x ± a, y ± b)

If a is positive then the point is moved right and if a is negative, the point is moved left. Also if b is positive, the point is moved up and if b is negative, the point is moved down

Step 1 is correct:

B (- 6, 1) ⇒ B' (- 6 + a, 1 + b) = B' (- 3, - 2)

Step 2 is not correct, Indira should have written the equations:

(-6 + a, 1 + b) = (-3, -2)

-6 + a = -3 and 1 + b = -2

a = 3 and b = -3

(x, y) ⇒ (x + 4, b - 3)

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the answer to this question is yes

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.