Point V is on line segment \overline{UW} UW

. Given UV=6,UV=6, UW=5x, UW=5x, and VW=4x-1,VW=4x−1, determine the numerical length of \overline{VW}.

VW

.

VW = 19

Step-by-step explanation: The segment UW has a point V between them, so:

UV + VW = UW

6 + 4x - 1 = 5x

4x + 5 = 5x

x = 5

The numerical length is

VW = 4x - 1

VW = 4(5) - 1

VW = 19

The measure, numerically, of VW is 19

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: