If $a>0$ and $b>0,$ a new operation $\nabla$ is defined as follows:$$a \nabla b = \frac{a + b}{1 + ab}.$$For example,$$3 \nabla 6 = \frac{3 + 6}{1 + 3 \times 6} = \frac{9}{19}.$$Calculate $(1 \nabla 2) \nabla 3.$

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

just keep asking questions until you have a better understanding.

step-by-step explanation: