For 1- 9: Let f(x) = 2x-1, g(x) = 3x, and h(x) = x^2 + 1. Compute the following: 1. f(g(-3))
2. fſh(7))
3. (gºh)(24)
4. f(g(h(2)))
5. h(g(f(5))
6. g(f(h(-6)))
7. f(x + 1)
9. h(x-2)
8. g(3a)

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

step-by-step explanation:

7

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.