For which values of a the system has at least one solution: x≤7 x≥a urgent pls help now

We have the system:

x ≤ 7

x ≥ a

Now we want to find the possible values of a such that the system has, at least, one solution.

First, we should look at the value of a where the system has only one solution:

We can write the 2 sets as:

a ≤ x

x ≥ 7

So, writing both together:

a ≤ x ≤ 7

if a is larger than 7, we do not have solutions.

then a = 7 gives:

7 ≤ x ≤ 7

Here the only solution is 7.

Now, if a is smaller than 7, for example 5, we have:

5 ≤ x ≤ 7

Now x can take different values, so we have a lot of solutions.

Then the restrictions for a, such that the system has at least one solution, is:

a ≤ 7.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.