2 lines intersect. A horizontal line has points D, E, B. Line A C intersects that line at point E. Angle A E D is (x + 25) degrees and Angle A, E, B is (9 x + 10) degrees. What is the numerical sum of the degree measures of ∠DEA and ∠AEB? What are the numerical measures of the angles? x = m∠DEA = ° m∠AEB = °

What is the numerical sum of the degree measures of ∠DEA and ∠AEB?

180

What are the numerical measures of the angles?

x = 14.5

m∠DEA = 39.5°

m∠AEB =  140.5°

Step-by-step explanation:

x + 25 + 9x + 10 = 180

Subtract 35 from both sides and you get,

10x = 145

The divide both sides by 10 and you get,

x = 14.5

To get the angle measurements you plug x back into the angle equations which in this case is 14.5.

It would look like,

m∠DEA = (14.5 + 25) = 39.5

and,

m∠AEB = (9 (14.5) + 10) = 140.5

What is the numerical sum of the degree measures of ∠DEA and ∠AEB?

180

What are the numerical measures of the angles?

x = 14.5

m∠DEA = 39.5°

m∠AEB =  140.5°

Step-by-step explanation:

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!