1. You work with traffic engineers for DOT (the department of transportation) and is in charge of performing measurements and analyzing speeding on a busy road. After measuring the speeds and collected a very large data sample, the speed on that road was found to have a Gaussian distribution with an average of 67 mph and standard deviation of 4 mph. If the highway patrol plans to ticket anyone driving faster than 72 mph, what is the % of drivers that will exceed this limit?

The % of drivers that will exceed this limit is 10.56 %

Step-by-step explanation:

Let's start defining the random variable :

: '' The speed on that road ''

We know that can be modeled with a Gaussian distribution ⇒

~ ( μ , σ )

Where ''μ'' is the mean and ''σ'' is the standard deviation. Given that the average speed and the standard deviation of the problem are known we write :  

~

We are asked about (which is the % of drivers that will exceed this limit).

To find this probability we are going to make a standardization of the variable (also called a change of variables).

We are going to substract the mean to and then divide by its standard deviation :

P [(X-μ) / σ > (72 - μ) / σ] (I)

The new variable [(X - μ) / σ] is called Z.

Z can be modeled as

~

⇒ Replacing in (I) the values of the mean and the standard deviation :

=

The convenience of this is that we can find the probabilities of Z (which is a N(0,1) ) in any table on internet ⇒

Looking at any table we will find that ⇒

= 10.56 %

We find that the % of drivers that will exceed this limits is 10.56 %

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

did u ever get the answers? i need