Find two consecutive whole numbers that square root of 31 lies between.
answer this please.

The consecutive whole numbers that the square root of 31 lies between will be 5 and 6.

Consecutive numbers simply refers to the numbers that follow each other in a particular set.

The square root of 31 is 5.57

Therefore, it can be noted that 5.57 will be between 5 and 6.

Therefore, the numbers are 5 and 6.

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Given :

An irrational number , .

To Find :

Two consecutive whole numbers that square root of 31 lies between.

Solution :

We know , square root of 36 is 6.

Also, square root of 25 is 5.

Now, we can see that lies between 5 and 6. Also, both 5 and 6 are consecutive.

Therefore, between 5 and 6 is the solution.

Hence, this is the required solution.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841