Given triangle ABC with vertices A(−3, 0), B(0, 6), and C(4, 6). c
Find the equations of the three altitudes of the same triangle

-1/2x+y-8=0, y-0, 7/6x+y-6=0

Step-by-step explanation:

First we find the slope of side AB:

6-0/0-(-3) =2

Altitude CD is perpendicular to AB:

slope of CD=-1/slope of AB = -1/2

Since the altitude CD passes through the point C(4, 6), using the point-slope form of the equation of a line, the equation of CD is:

y-6= -1/2*(x-4)

-1/2x+y-8=0

This is the required equation of the altitude from C to AB. The rest of the equations are solved in the same way. Good luck!

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

step-by-step explanation: