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The Equation of line with points (4 , - 3) and slope 3/2  is y =  3/2 x - 9 Step-by-step explanation: Given equation of line as : y =-2/3 x + 6 ∵ Standard equation of line is give as y = a x + c Where m is the slope of line and c is the y-intercept Now, comparing given line equation with standard eq So, The slope of the given line = a =  -2/3 Again, The other line if passing through the points (- 2 , - 1 ) And  is perpendicular to given line So, for perpendicular lines condition , the products of slope of both lines = - 1 Let The slope of other line = m So,  m × a = - 1 Or, m × -2/3 = - 1 So, m =  -1/-2/3 ∴ m =  3/2 Now, Again The line n is parallel to the line m and passes through the points (4 , - 3) ∵ Line n parallel to line m so, The slope of both are equal Let The slope of line n is M So, M = m =   3/2 So, The equation of line written as y = M x + c Or, - 3 = 3/2  ( 4 ) + c Or, - 3 = 3*4/2 + c Or, - 3 = 6 + c Or, c = - 3 - 6 ∴ c = - 9 So, Equation of line with points (4 , - 3) and slope 3/2 is y =  3/2 x - 9 Hence , The Equation of line with points (4 , - 3) and slope 3/2  is y = 3/2  x - 9                               HOPE IT HELPS (◕‿◕✿)                                                 SMILE!!

I’m pretty sure it’s i think : /