Show so that the expression of cos4A in term of SinA is 8Sin^4 - 8Sin^2A + 1 plz solve anyone.. I really need this answer

Step-by-step explanation:

L

H

S

=

cos

4

x

=

2

cos

2

(

2

x

)

−

1

=

2

(

cos

(

2

x

)

)

2

−

1

=

2

(

2

cos

2

x

−

1

)

2

−

1

=

2

(

4

cos

4

x

−

4

cos

2

x

+

1

)

−

1

=

8

cos

4

x

−

8

cos

2

x

+

2

−

1

=

8

cos

4

x

−

8

cos

2

x

+

1

=

R

H

S

Again

L

H

S

=

cos

4

x

=

2

cos

2

(

2

x

)

−

1

=

2

(

1

−

2

sin

2

x

)

)

2

−

1

=

2

(

1

−

4

sin

2

x

+

4

sin

4

x

)

−

1

=

2

−

8

sin

2

x

+

8

sin

4

x

−

1

=

8

sin

4

x

−

8

sin

2

x

+

1

=

R

H

S

sin

2

x

+

cos

2

x

=

1

cos

2

x

=

1

−

sin

2

x

substitute in the equation as follows

8

cos

4

x

−

8

cos

2

x

+

1

=

8

cos

2

x

(

cos

2

x

−

1

)

+

1

=

8

(

1

−

sin

2

x

)

(

1

−

sin

2

x

−

1

)

+

1

=

8

(

1

−

sin

2

x

)

(

−

sin

2

x

)

+

1

=

8

sin

4

x

−

8

sin

2

x

+

1

312312

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c