An airplane lands on a runway with a velocity of 150 m/s. How far will it travel until it stops if its rate of deceleration is constant -3m/s2?

3750 m

Step-by-step explanation:

This question can be solved using law of equation of motion

where v is the final velocity

u is the initial velocity

a is the acceleration

and

s is the distance travelled

________________________________

given

final velocity = v = 0 since it is given that plane stops

u = 150 m/s

a = -3m/s2

using the above values in the given equation

Thus, plane will travel 3750 m before it stops.

step-by-step explanation: