J is the midpoint of CT
С
J
T
If:
CJ = 5x – 3 and
JT = 2x + 21
Find CT.

CT=37

Step-by-step explanation:

5x-3 = 2x+21

-2x

3x-3 = 21

+3

3x = 24

÷3

× = 8

5(8) - 3 = 37

2(8) +21 =37

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

michael scott & dwight schrute

step-by-step explanation:

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