I’ll give Jim has ten more dollars than Gail. Together they have at most twenty-seven dollars. A. Determine the possible amounts of money Gail could have.
B. Sketch the solution on a number line.

see below

Step-by-step explanation:

Let g= amount that gail has

j = g+10

j+g ≤ 27

Substitute  the first equation into the inequality

g+g+10 ≤ 27

2g + 10 ≤ 27

Subtract 10 from each side

2g≤ 17

Divide by 2

g≤ 8.5

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

cant open file sorry!

step-by-step explanation: