Write an equation for the line containing (7,7) and (2,-3).

y = 2x - 7

Step-by-step explanation:

To find the line equation we assume that its form is y = m*x + b. Where m is the slope and b is the independent variable that intercepts the Y axis.

If we have two points as P1=(x1,y1) and P2=(x2,y2) we can use the slope formula as:

m = (y2-y1)/(x2-x1)

The points given are P1=(7,7) and P2=(2,-3), then the using the slope formula we obtain:

m = (-3-7)/(2-7)

m = (-10)/(-5)

m = 2

By now the equation is y = 2x + b. To find the value of b we have to replace in the equation any point, in this case i am using P2:

-3 = 2*(2) + b

-3 = 4 + b

-3 -4 = b

-7 = b

Therefore the equation of the line is:

y = 2x - 7

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice