X^2+6x≤-5 with an explanation pls

−5≤x≤−1

Step-by-step explanation:hope that helps :)))

x2+6x=−5

x2+6x−(−5)=−5−(−5)(Subtract -5 from both sides)

x2+6x+5=0

(x+1)(x+5)=0(Factor left side of the equation)

x+1=0 or x+5=0(Set factors equal to 0)

x=−1 or x=−5

Check intervals in between critical points. (Test values in the intervals to see if they work.)

x≤−5(Doesn't work in original inequality)

−5≤x≤−1(Works in original inequality)

x≥−1(Doesn't work in original inequality)

−5≤x≤−1

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is

other answer is correct. i had used the radius of the radius somehow. a website: