Triangle A'B'C' is a rotation of triangle ABC by 60 degrees using Q as the center. Select ALL statements that MUST be true.
-Angle ABC is 60 degrees.
-Angle AQA' is 60 degrees.
-Points C and C' coincide.
-Triangles ABC and A'B'C' are congruent.
-Angle ABC is congruent to angle A'B'C'
-Segment BC is congruent to segment B'C'
-Segment BQ is congruent to segment C'Q.
-Segment AQ is congruent to segment A'Q.

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  see below

Step-by-step explanation:

When a figure is rotated about a center point, the central angle formed by any point on the figure and the corresponding image point will be the rotation angle. Every image point is the same distance from the center of rotation that the pre-image point was. No lengths or angles are changed: rotation is a "rigid motion", so the rotated figure is congruent with the original.

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-Angle AQA' is 60 degrees.

-Triangles ABC and A'B'C' are congruent.

-Angle ABC is congruent to angle A'B'C'. (this is one of the angles of the congruent triangles)

-Segment BC is congruent to segment B'C'

-Segment AQ is congruent to segment A'Q.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

ddd

step-by-step explanation: