Find the area, A, of the sector intercepted by a central 0 = pi/5 for a circle with radius, r = 19.4 cm.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

the answer is 15.50 for one mile

b) is slope: 0   y- intercept 15.5

hd extra 3-7 x d en is the answer