Mathematics, 20.10.2020 14:01 Mrblunt5613
Please help tysm!
Why is the domain of f(x) = cube root of x NOT restricted while the domain of g(x) = sqrt(x) is?
1. It is easier to take the square root of a number than it is to take the cube root of a number.
2. We cannot take the square root of any numbers except for those that are perfect squares, such as 0, 1, 4, 9, 16, etc.
3. This is not true. The domains of both functions are restricted since the cube root and square root of negative numbers are both not real.
4. The cube root of a negative number is still a real number, but the square root of a negative number is not real.
Answers: 2
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Please help tysm!
Why is the domain of f(x) = cube root of x NOT restricted while the domain of g(x...
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