Identify an equation in point-slope form for the line perpendicular to y=-1x +11 that passes through (4, -8).
O A. y +8 = 2(x-4)
B. y - 4 = 2(x+8)
O C. y+8 = {(x-
-4)
O D. 7-8 = {(x + 4)

C

Step-by-step explanation:

Perpendicular lines have the exact opposite slope of the other equation.

So the slope will be x or 1x. Plug in

-8 = 1(4) + b (b represents y-intercept) like y=mx+b

-8 = 4 + b (subtract 4 on both sides)

-12 = b

The equation is y = x - 12

C

solve

y + 8 = x - 4 (subtract 8 on both sides)

y = x - 12

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

i dont know men

step-by-step explanation: