Of 1000 randomly selected cases of lung cancer, 838 resulted in death within 10 years. Construct a 95% two-sided confidence interval on the death rate from lung cancer. (a) Construct a 95% two-sided confidence interval on the death rate from lung cancer. Round your answers to 3 decimal places. (b) Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03

0.8152 ≤ p ≤ 0.8608

579

Step-by-step explanation:

Given the following :

Samples size n = 1000

Deaths within 10 years, p = 838

α = 95%

Construction a two way confidence interval:

p ± Zα/2 * √p(1-p) / n

point estimate p = 838/n = 838/1000 = 0.838

Z0.05/2 = Z0.025 = 1.96

0.838 - 1.96√0.838(1-0.838) / 1000

0.838 - 1.96*0.0116514 = 0.8152

0.838 + 1.96√0.838(1-0.838) / 1000

0.838 + 1.96*0.0116514 = 0.8608

0.8152 ≤ p ≤ 0.8608

b) Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03

Error (E) = 0.03

To find the samome size, use the relation:

n = (Zα/2 / E)² * p(1-p)

n = (1.96/0.03)² * 0.838(1-0.838)

n = (1.96/0.03)² * 0.838 * 0.162

n = 4268.4444 * 0.838 * 0.162

n = 579.46

n = 579

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

triangle and cube

step-by-step explanation: