Suppose the wedding planner assumes that 5% of the guests will be pollotarian so she orders 30 pollotarian meals. What is the approximate probability that more than 5% of the guests are pollotarian and therefore she will not have enough pollotarian meals

0.0787 is the probability that more than 5% guests are pollotarian.

Step-by-step explanation:

Solution:

Given:

Assume 5% of guests will be pollotarian.

She order 30 pollotarian meals.

Expected proportion of the guest would be expected to be proletarian  =3.5%

P = 0.035

n = sample size = 300

Standard error = √(p(1-p)/n)

                         = √(0.035(1-0.035)/300)

                        = √(0.033775/300)

                       = √0.0001125

                        = 0.0106

Therefore, proportion expected to be pollotarian are 0.035 give,

Or take 0.0106.

Probability that more than 5% of guests are pollotarian:

P( x> 0.05) = 1- p(x < 0.05)

                  = 1 – p ( z < ( 0.05 – 0.035 )/ 0.0106)

                  = 1 – p( z < 1.4137)

                   = 1 – 9213

                   = 0.0787

0.0787 is the probability that more than 5% guests are pollotarian.

can you rephrase the question ? it is unclear : -)

step-by-step explanation: