Three trolley tours leave from the same stop at 9:00 am. Tour A returns to the stop every 75 minutes, Tour B returns every 60 minutes, and Tour C returns every 40 minutes. In how many hours will all three tours return to the stop at the same time?

Given :

Three trolley tours leave from the same stop at 9:00 am.

Tour A returns to the stop every 75 minutes, Tour B returns every 60 minutes, and Tour C returns every 40 minutes.

To Find :

In how many hours will all three tours return to the stop at the same time.

Solution :

We know, they will return to the stop at the same time is the L.C.M of three i.e 75, 60 and 40 minutes.

So, their L.C.M is :

L.C.M = 600 minutes.

Now, 600 minutes = 600÷60 hours = 10 hours.

Therefore, they will all meet at stop in 10 hours.

Hence, this is the required solution.

it reflected because of the glass maube

step-by-step explanation:

this doesn't make sense lol