Two bicyclist started racing towards each other when they were 98 miles apart. Three hours later they did not yet meet and the distance between them was 2 miles. How fast each of them biked if the speed of one of them was 3 mph slower than the other's? Please i beg u guys btw the wrong answer is 32 and 35 so dont do it
(i mark brainliest)

YES

Step-by-step explanation:

NO

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

table a is wierd

step-by-step explanation:

6*f