What is the sum of the proper factors of 132

9514 1404 393

  203

Step-by-step explanation:

The prime factorization is ...

  132 = 2·2·3·11

The exponents of these factors are 2, 1, 1, so the number of divisors is ...

  (2+1)(1+1)(1+1) = 12

Those divisors are ...

  1, 2, 3, 4, 6, 11, 12, 22, 33, 44, 66, 132

The proper factors are all but the first and last of these. Their sum is ...

  2 +3 +4 +6 +11 +12 +22 +33 +44 +66 = 203

The sum of proper factors of 132 is 203.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure