HELP PLEASEEE IM BEGGING YOU One year ago, a tiger cub was 5 feet shorter than its mother. However, it grew 2 feet, and now it’s mother is only twice its size. How big was the tiger cub one years ago?
This is algebra 1 btw...

The cub was 1 ft long a year ago.

Step-by-step explanation:

The tiger cub was 1 foot long a year ago.

One year ago, if the tiger cub was 1 foot:

1 ft = Cub

1 + 5 = 6 = Mother

Now:

1 + 2 = 3 = Cub

6 = Mother

The mother is now only twice as big as the cub, meaning that this solution is correct.

Solution using algebra:

One year ago:

x = Cub

x + 5 = Mother

Now:

x + 2 = Cub

x + 5 = Mother

We know the mother is now only twice as big as her cub.

2(x + 2) = x + 5

2x + 4 = x + 5

2x - x = 5 - 4

x = 1

Hope this helps!

One year ago, the cub was 1 ft

Step-by-step explanation:

One year ago:

The height of Mother tiger = x feet

Height of cub = x - 5

Now,

Height of cub = (x - 5) + 2 = x  -5 + 2 = x - 3

Height of mother  = Twice the cub size

                            x = 2*(x - 3)

x = 2x - 6

x + 6 = 2x

   6 = 2x - x

  6 = x

The height of Mother tiger =  6 feet

Height of cub = 6 - 5  = 1 feet

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

it is x=-4

step-by-step explanation: