Assume that a crucial machine part has a 5% rate of failure, based on company data. Since the part is so crucial, the company installs a second independent system with the same probability of failure as the first. What is the probability both systems will fail?

0.25%

Step-by-step explanation:

In order to calculate the probability of two separate events happening at the exact same time, you simply have to take the first probability and multiply it by the second one. Since both of these parts have the same probability of failure, we first need to turn that percentage into a decimal by dividing it by 100.

5% / 100 = 0.05

Now we multiply both probabilities together

0.05 * 0.05 = 0.0025 ... multiply by 100 to get percentage value

0.0025 * 100 = 0.25%

Finally, we can see that there is a 0.25% chance that both parts will fail at the same time.

answer: jasmine will bake 4/3 or 1 1/3 cookies in an hour

step-by-step explanation:

if u add 1/3 every 15 minutes after an hour u will have 4/3 or 1 1/3

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: