, 26.10.2020 22:40 michaela134

134d) Graph the hyperbola, identify the center, vertices, foci, and equations of the asymptotes 49y^2−25x^2−196y−200x−1429=0 IF YOU ARE GOOD AT MATH, PLEASE HEAD OVER TO MY PROFILE, IN THE QUESTIONS TAB AND ANSWER THE QUESTIONS STARTING FROM THE ONE MARKED 132B! best answers get marked 'brainliest'! Thank you!

Step-by-step explanation:

49y^2 - 25x^2 - 196y - 200x = 1429

49y^2-196y+196 - 25x^2-200x-400 = 1429+196-400

49(y-2)^2 - 25(x+4)^2 = 1225

(y-2)^2/25 - (x-4)^2/49 = 1

So now you know that you have an hyperbola with

center at (-4,2)

foci at (-4,2±)

vertices at (-4,2±5)

asymptotes 7y±20 = ∓5x+14

step-by-step explanation:

just multiply it

they go with it happens or they mite give a chance?

step-by-step explanation:

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