What is the probability that six consecutive integers will be chosen as the winning numbers in a lottery where each number chosen is an integer between 1 and 40 (inclusive)?

0.00000911843

Step-by-step explanation:

Since the number chosen is an integer between 1 and 40 (inclusive), it means that the number of terms is 40.

Thus; n = 40

Probability that 6 integers (r = 6) which is number of possible outcomes will be gotten without repetition is gotten by the combination formula which is;

C(n, r) = n!/(r!(n - r)!)

C(40, 6) = 40!/(6!(40 - 6)!)

C(40,6) = 3838380

Now, to select 6 consecutive integers, it can be done in different combinations such as;

(1 - 6, 2 - 7, 8 - 13,...e.t.c)

Total number of favorable outcomes will be 35.

Now,probability that six consecutive integers will be chosen as the winning numbers is;

P(that six consecutive integers will be chosen as the winning numbers) = number of favorable outcomes/number of possible outcomes = 35/3838380 = 0.00000911843

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c

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