The plans for constructing a raised vegetable garden use corrugated metal in a wooden frame. The finished garden is 4 feet long, 30 inches wide, and
32 inches tall.
The metal is only used on the lateral faces, so how many square feet of metal
should be purchased? Round to the nearest square foot

35 square feet of metal should be purchased

Step-by-step explanation:

Let us use the fact above to solve the question

∵ The garden is 4 feet long

∵ Its wide is 30 inches

→ Change it to feet by divide it by 12

∴ Its wide = 30 ÷ 12

∴ Its wide = 2.5 feet

∵ It is 32 inches tall

→ Change it to feet by divide it by 12

∴ Its tall = 32 ÷ 12

∴ Its tall = 8/3 feet

∵ The perimeter of the rectangle = 2(length + width)

∵ Length = 4 feet and wedth = 2.5 feet

∴ The perimeter of the base = 2(4 + 2.5)

∴ The perimeter of the base = 13 feet

→ Substitute it in the rule above

∴ L.A = 13 × h

∵ The height = 8/3 feet

∴ L.A = 13 × 8/3

∴ L.A = 34.666667 feet²

→ Round it to the nearest square foot

∴ L.A = 35 feet²

∴ 35 square feet of metal should be purchased

i think it might be a but you might want a second opinion

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)