A healthy human heart beats about 1,533,000 times in a year. A sparrow's heart beats about 241,776,000 times in a year.

About how many times faster does the sparrow's heart beat compared to the human heart?

Estimate using a single digit times a power of 10.

2x108

or about 100 times faster

2x10

=1 x 102

0 2x10°

2x106

= 1 x 103

or about 1,000 times faster

2x108

2x105

=1 103

or about 1,000 times faster

2x109

2x105

=1 104

or about 10,000 times faster

About 100 times faster

=1 x 10²

Step-by-step explanation:

Estimate using a single digit times a power of 10.

We approximate to the nearest whole number

A healthy human heart beats about 1,533,000 times in a year.

= 1.533 × 10⁶

As a single digit = 2.0 × 10⁶

A sparrow's heart beats about

241,776,000 times in a year.

= 2.41776 × 10⁸

As a single digit = 2 × 10⁸

About how many times faster does the sparrow's heart beat compared to the human heart?

We find the difference in their powers of 10

= ( 10^8 - 6)

= 10²

This means the sparrows heart beats at about

1 × 10² or a 100 times faster

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

answer: 3.26019516

step-by-step explanation: