If 1/12th of a page is 1/3 of a minute, you have to ask what number do you multiply 1/12th by to equal 1?
So then multiply both 1/12th and 1/3rd by 12. You get 12/12 and 12/3
So every 4 minutes he writes one page.
b. the average rate of change of f(x) is less than the average rate of change of g(x).
since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)
so the change in y-value for function f is (6 )) = 9.
the table tells usg(-2) = 1g(1) = 31
so the change in y-value for function g is (31 -1) = 30.
the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).
c > -10.55