Mathematics, 31.10.2019 02:31 mobslayer88
What values of x and y satisfy −13/3x−2y=7 and 3x+2/5y=5 simultaneously?
Answers: 1
![3x+\frac{2}{5} y=5 \\ [tex]3x+\frac{2}{5} (\frac{-13}{6}x - \frac{7}{2})=5 \\ 3x + \frac{-26}{30}x- \frac{14}{10} =5 \\ \frac{90}{30}x +\frac{-26}{30}x- \frac{42}{30} = \frac{150}{30} \\ \frac{64}{30}x - \frac{42}{30} = \frac{150}{30} \\ (\frac{64}{30}x - \frac{42}{30})+\frac{42}{30} = (\frac{150}{30})+\frac{42}{30} \\ \frac{64}{30}x= \frac{192}{30} \\ (\frac{64}{30}x)*30= (\frac{192}{30})*30 \\ 64x=192 \\ 64x/64 = 192/64 \\ x=3](/tpl/images/0353/6757/f8dd4.png)
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What values of x and y satisfy −13/3x−2y=7 and 3x+2/5y=5 simultaneously?...
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