A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart and fly directly toward each other. In how many hours will they meet? plz help
times almost up

The time the two planes will meet is 1.43 hours

Step-by-step explanation:

Given;

speed of the first plane in positive direction, = 40 mph

speed of the second plane in negative direction(opposite direction) = -100 mph

distance between the two planes = 200 miles

Let the time the two planes will meet = t

the position of the first plane at this time "t" = 40t

the position of the second plane at this time "t" = -100t

(40t)><(-100t), this space between them is 200 miles.

Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.

40t - (-100t) = 200

40t + 100t = 200

140t = 200

t = 200 / 140

t = 1.43 hours

Therefore, the time the two planes will meet is 1.43 hours

step-by-step explanation:

consider the parallelogram shown in the attached image.

in the parallelogram hijk, the length of hk is given as,

from the properties of parallelogram we know that the opposite sides of a parallelogram are parallel to each other and are equal in measure.

therefore, the length of the side ij must be equal to the length of the side hk and that is .

hence, the expression for the length of ij confirms that hijk is a parallelogram.