A rectangle has a length that is three feet more than twice it's width. The perimeter of the rectangle is 78 feet. State the value for the width.

Let the width of the rectangle be 'w'

According to the question length of the rectangle (l) is three feet more than twice it's width;

l = (2w + 3) ft

Perimeter of rectangle = 78 ft

Formula of perimeter of rectangle = 2(Length + Width)

So,

Width of the rectangle (w) = 12 ft

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

what are the