Solving systems of linear equations algbraically.

(3,-6)

Step-by-step explanation:

  [1]    x - 2y = 15

  [2]    2x + 4y = -18

Graphic Representation of the Equations :

   -2y + x = 15        4y + 2x = -18  

Solve by Substitution :

// Solve equation [1] for the variable  x

 [1]    x = 2y + 15

// Plug this in for variable  x  in equation [2]

  [2]    2•(2y+15) + 4y = -18

  [2]    8y = -48

// Solve equation [2] for the variable  y

  [2]    8y = - 48

  [2]    y = - 6

// By now we know this much :

   x = 2y+15

   y = -6

// Use the  y  value to solve for  x

   x = 2(-6)+15 = 3

Solution :

{x,y} = {3,-6}

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x