Find the slope of the line perpendicular to the graph of y− 1/5 x=7

help due soon

Step 1: We need to covert the current equation to slope-intercept form*.

Step 2: Now that we have our equation in slope-intercept form, we can determine the perpendicular slope of the line.

Our new slope is now -5.

*Slope-intercept form: y = mx + b

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^