3.3 Practice - Piecewise Functions Find the value of the given function at the indicated domain value.
-X2 - 5x + 2, x < 1
2x2 - 2x + 1,
xs-6
g(x) = x3 - 5x, 1 < x < 11
h) =
3x – x3 -3 3x - 16,
X > 11
(2x - (x - 100
x > 1
1. g(1) =
2. g(11) =
3. h(5) =
4 h(-10) =
5. g(-1) =
6. h(0) =
7. g(20) =
8. h(-4)=

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.