PLZ HELP Use your knowledge of solving equations with variables on both sides of the equal sign to solve the following problem.
A square and a rectangle have the same perimeter. The square has a side length of 6x units. The rectangle has a length of (2x + 4) units and a width of 16 units. What will be the perimeter of both the rectangle and the square? and don't just give me an answer, I need to understand this.
Answer choices:
26
56
48
2

a

Step-by-step explanation:

48

Step-by-step explanation:

Perimeter of square = 4 x 6x

Perimeter = 24x

P = 2l + 2w

P = 2(2x + 4) + 2(16)

P = 4x + 8 + 32

P = 4x + 40

Perimeter of square = perimeter of rectangle

24x = 4x + 40

-4x      -4x

20x = 40

20      20

x = 2

Perimeter of square = 24x

Perimeter of square = 24(2)

Perimeter of square = 48

Perimeter of rectangle = 4x + 40

Perimeter of rectangle = 4(2) + 40

Perimeter of rectangle = 8 + 40

Perimeter of rectangle = 48

i think c. but don't trust it.

step-by-step explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)