M(n+r)=s solve for n. Show two methods.

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Step-by-step explanation:

1. Undo the operations done to n, in reverse order. Here, n has r added and the sum is multiplied by m. First we divide by m, then we subtract r.

  m(n+r) = s . . . given

  n +r = s/m . . . divide by m

  n = (s/m) -r . . . subtract r

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2. Eliminate the parentheses, then proceed as above. Subtract the added term, then divide by the coefficient of n.

  m(n+r) = s

  mn +mr = s . . . eliminate parentheses

  mn = s -mr . . . subtract the added term

  n = (s -mr)/m . . . divide by the coefficient of n

answer: i'm not sure

step-by-step explanation: