Addison painted her room. She had 50 square meters to paint, and she painted at a constant rate. After 2 hours of
painting, she had 35 square meters left.
Let y represent the area (in square meters) left to paint
after x hours.
Complete the equation for the relationship between
the area and number of hours.
y =

What is the image of c for a 90° counterclockwise rotation about a? (3, 7) (-1, 3) (7, 3)

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .

If f(x) = 2x + 8 and g(x) = x4, what is (gº)?