10m^2-20m+48=0 solve by completing the square please show your work please.

m = {-6, -4}

Step-by-step explanation:

Subproblem 1:

Set the factor '(6 + m)' equal to zero and attempt to solve:

Simplifying

6 + m = 0

Solving

6 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + m = 0 + -6

Combine like terms: 6 + -6 = 0

0 + m = 0 + -6

m = 0 + -6

Combine like terms: 0 + -6 = -6

m = -6

Simplifying

m = -6

Subproblem 2:

Set the factor '(4 + m)' equal to zero and attempt to solve:

Simplifying

4 + m = 0

Solving

4 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + m = 0 + -4

Combine like terms: 4 + -4 = 0

0 + m = 0 + -4

m = 0 + -4

Combine like terms: 0 + -4 = -4

m = -4

Simplifying

m = -4

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b