A 18,000 gallon swimming pool contains 7000 gallons of water when a hose is placed in the pool and begins adding water at a rate of 1100 gallons per hour Use the Segment tool to plot a graph representing the volume of water in the pool over time from when the hose is placed in the pool until the pool is full.

Volume of Water in Pool

(0, 7000); (10, 18000)

Step-by-step explanation:

Lets first start by breaking the problem down

Breaking the problem down

We add 1100 gallons for every hour

The pool already contains 7000 gallons

Our goal is 18000 gallons.

Make an equation

y = mx + b

In this case we're lucky as all of these are given.

Our slope of m is how many of gallons we gain for every x value (hours)

So plugging it in we can rewrite it so far as

y = 1100x + b

Now our b value is our y-intercept which is what we start with at x = 0 which is also where the value touches our y-axis.

In this case at 0 hours passed we have 7000 gallons thus 7000 is our b.

We can plug it in and rewrite as follows

y = 1100x + 7000

Now what we want to solve for is our y so we plug 18,000 in for y and solve by getting x alone

        y = 1100x + 7000

18000 = 1100x + 7000

-7000               -7000

11000 = 1100x

Divide both sides by 1100 and you have your hours until its full

10 = x

So at 10 hours the 18000 gallon pool will be full,

As such we can determine our second point as (10, 18000)

Now because we know our y-intercept we can use that to find the other point.

The line intercepts the y axis (0, y) at 7000, and as such our point is

(0, 7000)

Putting them together we have point A and point B solved

A(0, 7000) B(10, 18000)

Note the points are (x value, y value)

Hope this helps, if you have any more trouble leave a comment and I'll help you further

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer