Write an equation in slope-intercept form of the line that passes through the
points (-5, -11) and (6,11).

Slope=2.

Step-by-step explanation:

Slope=y1-y2/x1-x2

Where

X1,y1,=(-5, -11) X2,y2=(6,11).

Slope=-11-11/-5-6

=-22/-11

=22/11

=2

Slope is 2

2

Step-by-step explanation:

Here,

x₁ = (- 5) and x₂ = 6

y₁ = (- 11) and y₂ = 11

Now,

Slope

= y₁ - y₂ ÷ x₁ - x₂

= (- 11) - ( 11) ÷ (- 5) - ( 6 )

= - 11 - 11 ÷ - 5 - 6

= - 22 ÷ - 11

= 2 ÷ 1 = 2

Thus, Slope is 2

-TheUnknownScientist

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

the answer will be b x² +x-1

step-by-step explanation: